Wednesday, April 3, 2013

Two digit multiplication with 25

Two digit Multiplication with 25

When you are multiplying with 25, you need to remember table 4 and table 25.

Table 4 is for division and Table 25 for multiplication.

Just you need to remember
25 x 1 = 25
25 x 2 = 50
25 x 3 = 75

Let me take one example

Ex 1. 13 x 25 = ?

Take 13 and divide with 4.

There are 3 fours in 13 and remainder is 1

result = 3x100 + 25 x 1 = 300 + 25 = 325

So you need to find how many 4s are there in the number and what is remainder.

Let us try one more example

Ex 2 : 22 x 25 = ?

5 fours are there in 22 and remainder is 2

result = 500 + 2 x 25 = 550

Rule is simple

step 1 : find remainder and how many fours are there in the number
step 2 : no. of 4s x 100 + remainder x 25

Let me take two more examples

Ex 3 : 35 x 25 = 8 x 100 + 3 x 25 = 875
Ex 4 : 48 x 25 = 12 x 100 + 0 x 25 = 1200

conclusion :

if remainder is 0 last two digits 00
if remainder is 1 last two digits 25
if remainder is 2 last two digits 50
if remainder is 3 last two digits 75

Last example

Ex 5: 81 x 25 =  2025
Similar way we can do for 50. Lets see this in next post

Monday, April 1, 2013

Two digit multiplication with 99

Today we will try multiplication with 99.

Ex 1 : 23 x 99

Multiplication with 99 can be done by subtraction

result = 23 -1 / 99 - (23 -1 )
          = 22 /  99-22
          = 22 / 77
          = 2277

How to do?

1. Just subtract 1 from number(not 99). So here other than 99 is 23 
Hence 23 - 1 = 22

2. Subtract resultant value from 99
 Hence 99 - 22 =  77

Result = 22 / 77 = 2277

Please note here also there is no carry forward

Try following examples

56 x 99
34 x 99
76 x 99
85 x 99

Lets see how to multiply with 25 in next post

Saturday, March 30, 2013

Two digit multiplication in 2 seconds

Ex : 33 x 37

This is very easy. Matter of seconds to complete the multiplication

33 x 37 = 3 x 4 / 7 x 3
             = 12 / 21
             = 1221

Please remember this is special case

You can apply this method if it satisfies two conditions

1. ten's digit should be same
2. sum of 1's digits should be 10

In 33 x 37

10's digit is 3 in both number
sum of 1's digit = 3 + 7 = 10

Let  us try one more example

42 x 48 = 20 / 16 = 2016

What exactly you are doing is

1's digit number in the result = product of 1's digit = 2 x 8 = 16
10's digit number in the result = 10's digit number x (10's digit number  + 1)
                                               = 4 x ( 4 + 1) = 4 x 5 = 20

No carry forward. Just you are taking numbers as it is
i.e result = 2016

Try following examples  and check the result

Ex 1.   51 x 59 = ?
           23 x 27 = ?
           94 x 96 = ?
           76 x 74 = ?


          

Wednesday, March 27, 2013

Today let me try with base 30.

Ex : 34 x 37

step 1: base is 30
step 2: 34 x 37
     +4    + 7

step 3: 34 + 7 / 4 x 7
          = 41 / 28
          = 41 x 3 /  28 ( multiply with 3 as base is 30 )
          = 123 + 2 / 8  ( carry forward 2 )
          = 125/8  
          = 1258
  
Actually these many steps not required. For your understanding purpose, I am explaining step by step.

 One more example

Ex 2 : 33 x 37

base = 30
result = 33 + 7 /  7 x 3
          = 40 / 21
          = 40 x 3 / 21    ( multiply with 3 as base is 30 )
          = 120 / 21        ( carry forward 2 )
          = 1221


we can do second example in  very simple way. How?

Wait till next post...

Monday, March 25, 2013

Did you find answer for 16 x 14 ?


Base for 16 x 14 is 10
               +6   +4

Unit's place digit = 6x4 = 24
10's place digit  = 16+4 = 20o

result = 20 / 24  = 20+2 / 4  ( 2 carry forward )
          = 224

Base method is very useful in squaring number.

Now what is the result of 23 x 22 ?


Here what is the base? 20

23 x 22
 +3    +2

unit's place digit = 3x2 = 6
10s place digit = 23 + 2 = 25
result = 25 / 2 = 252

Is that correct? No

Please note in this examples 20 is the base. So you have to multiply 10's digit with 2


Correct method :
10's place digit = 23 + 2 = 25 x 2  ( As 20 is base, multiply with 2 )

result = 50 / 6 = 506

Now you tell me if the base is 30, multiply with ?

if the base is 30, multiply 10's digt  with 3
if the base is 40, multiply 10's digt with 4



Sunday, March 24, 2013

Two digit multiplication - special case

I would like to introduce special case in multiplication. This is base method multiplication.

What is base method multiplication?

Let me explain by taking one example.

Ex : 15 x 17

15 = 10 + 5
17 = 10 + 7

So here 10 is base

15 x 17
 +5   +7

 unit digit = 5 x 7 = 35
10's digit = 15 + 7 = 22

So result = 22 / 35
Please note in units place two digits are there. As I mentioned in earlier posts 3 should be carried.

So result = 22+3 / 5 = 25 / 5 = 255

So now you try for  16 x 14 = ?.

Bottom line is express both number into base of some number. Here that is 10
15 = 10 + 5 and 17 = 10 + 7

Unit place number is multiplication of  numbers of above the base i.e. 5 x 7 = 35
10's place number is 15 + 7 or 17 + 5 = 22

If you understand this method, multiplication matter of seconds. Try and expertise this. Next methods depends on this method.



Wednesday, March 20, 2013

Two digit multiplication

I am back...

Lets look at two digit multiplication in generic way

Ex : 23 x 45

Here two numbers are there
first number :  23
first digit  : 3 second digit : 2

second number : 45
first digit  : 5 second digit :4

Result :

first digit = first digit x first digit = 3 x 5 = 15
second digit = first digit x second digit  + second digit x first digit
                    = 3 x 4 + 2 x 5 = 12 + 10 = 22
third digit = second digit x second digit = 2 x 4 = 8

wherever two digits are there in result, carry one digit to next place.

first digit in result = 15 = 5 and 1 carry forward to next place
second digit in result = 22 + 1 ( carry forward )
                                 = 23 = 3 and 2 carry forward to next place
third digit in result = 8 + 2 ( carry forward )
                              = 10 = 0 and 1 carry forward to next place

So the result is 1035


result = second digit x second digit / first digit x second digit + second digit x first digit / first digit x first digit


In simple terms

ab x  cd = ac / ad + bc / db


b and d are first digits of numbers ab and cd
a and c are second digits of numbers ab and cd